## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$14\sqrt{3} \text{ and } 28$
Since the given acute angle of the right triangle is $30^o,$ then the side opposite this angle is half the hypotenuse. Hence, the hypotenuse is $28.$ The other acute angle measures $60^o.$ The side opposite this angle, $a,$ is $\dfrac{\sqrt{3}}{2}\cdot c,$ where $c$ is the hypotenuse. Hence, \begin{array}{l}\require{cancel} \dfrac{\sqrt{3}}{2}\cdot c=a \\\\ \dfrac{\sqrt{3}}{2}\cdot 28=a \\\\ 14\sqrt{3}=a .\end{array} Hence, the missing sides have measure $14\sqrt{3} \text{ and } 28$ units.