Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.7 The Distance Formula, the Midpoint Formula, and Other Applications - 10.7 Exercise Set: 11

Answer

$a=8$

Work Step by Step

In the given right triangle, $a$ and $b$ are the legs and $c$ is the hypotenuse. Using $a^2+b^2=c^2$ or the Pythagorean Theorem, with $ b=15 $ and $ c=17 ,$ then \begin{array}{l}\require{cancel} a^2+b^2=c^2 \\\\ a^2+15^2=17^2 \\\\ a^2+225=289 \\\\ a^2=289-225 \\\\ a^2=64 \\\\ a=\sqrt{64} \\\\ a=8 .\end{array}
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