Answer
$$2x-2\sqrt{x^2-4}$$
Work Step by Step
Simplifying the expression using the rules of radicals, we obtain:
$$ \left(\sqrt{x+2}-\sqrt{x-2}\right)^2\\ \left(\sqrt{x+2}\right)^2-2\sqrt{x+2}\sqrt{x-2}+\left(\sqrt{x-2}\right)^2\\ 2x-2\sqrt{x^2-4}$$