## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$$12+4\sqrt{5}$$
We are told: $$f(x)=x^2$$ Thus, plugging in the given value for $x$, we find: $$\left(\sqrt{2}\right)^2+2\sqrt{2}\sqrt{10}+\left(\sqrt{10}\right)^2\\ 12+4\sqrt{5}$$