## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 10 - Exponents and Radicals - 10.5 Expressions Containing Several Radical Terms - 10.5 Exercise Set: 34

#### Answer

$4\sqrt{6}+4\sqrt{10}$

#### Work Step by Step

Using $a(b+c)=ab+ac$ or the Distributive Property, the given expression, $4\sqrt{2}(\sqrt{3}+\sqrt{5}) ,$ is equivalent to \begin{array}{l}\require{cancel} 4\sqrt{2(3)}+4\sqrt{2(5)} \\\\= 4\sqrt{6}+4\sqrt{10} .\end{array}

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