## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Using the Product Rule of the laws of exponents which is given by $x^m\cdot x^n=x^{m+n},$ then \begin{array}{l}\require{cancel} x^{1/5}\cdot x^{2/5} \\\\= x^{\frac{1}{5}+\frac{2}{5}} \\\\= x^{\frac{3}{5}} \\\\= x^{3/5} .\end{array} Hence, $\text{ Choice A .}$