Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Test: Chapter 1: 17

Answer

$\dfrac{2}{3}$

Work Step by Step

Multiplying the given expression,$-\dfrac{2}{3}$, by $-1$, then its opposite is \begin{array}{l}\require{cancel} -\left( -\dfrac{2}{3} \right) \\\\= \dfrac{2}{3} .\end{array}
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