Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Study Summary - Practice Exercises - Page 75: 28

Answer

$120\div(-10)\cdot2-3(4-5)=-21$

Work Step by Step

According to the order of the operations simplify as follows: $\begin{array}\,{120\div(-10)\cdot2-3(4-5)}&{}=120\div(-10)\cdot2-3(-1) \newline &{}=-12\cdot2-3(-1) \newline&{}=-24+3 \newline&{}=-21\end{array}$
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