Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Study Summary - Practice Exercises - Page 73: 15



Work Step by Step

$\bf{\text{Solution Outline:}}$ To divide the given expression, $ 15\div\dfrac{3}{5} ,$ multiply the dividend by the reciprocal of the divisor. $\bf{\text{Solution Details:}}$ Multiplying the dividend and the reciprocal of the divisor, the given expression is equivalent to \begin{array}{l}\require{cancel} 15\div\dfrac{3}{5} \\\\= 15\cdot\dfrac{5}{3} \\\\= \cancel3(5)\cdot\dfrac{5}{\cancel3} \\\\= 25 .\end{array}
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