Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Review Exercises: Chapter 1: 13

Answer

The answer is $-15$.

Work Step by Step

To evaluate, substitute the given value of the variable in the expression, then perform the operation: \begin{align} -10 + a^2 \div (b + 1) &= -10 + (5)^2 \div ((-6) + 1) &&\text{Substitute} \\ &= -10 + 25 \div (-5) &&\text{Evaluate} \\ &= -10 + (-5) \\ &= \color{red} {-15} &&\text{Evaluate} \end{align}
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