Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - Mid-Chapter Review - Mixed Review - Page 37: 14


$3 \left( 3c+4d+1 \right)$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Get the $GCF$ of the given expression, $ 9c+12d+3 .$ Divide the given expression and the $GCF.$ Express the answer as the product of the $GCF$ and the resulting quotient. $\bf{\text{Solution Details:}}$ The $GCF$ of the terms is $ 3 $ since it is the highest number that can evenly divide (no remainder) all the given terms. Factoring the $GCF= 3 ,$ the expression above is equivalent to \begin{array}{l}\require{cancel} 3 \left( \dfrac{9c}{3}+\dfrac{12d}{3}+\dfrac{3}{3} \right) \\\\= 3 \left( 3c+4d+1 \right) .\end{array}
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