## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$3 \left( 3c+4d+1 \right)$
$\bf{\text{Solution Outline:}}$ Get the $GCF$ of the given expression, $9c+12d+3 .$ Divide the given expression and the $GCF.$ Express the answer as the product of the $GCF$ and the resulting quotient. $\bf{\text{Solution Details:}}$ The $GCF$ of the terms is $3$ since it is the highest number that can evenly divide (no remainder) all the given terms. Factoring the $GCF= 3 ,$ the expression above is equivalent to \begin{array}{l}\require{cancel} 3 \left( \dfrac{9c}{3}+\dfrac{12d}{3}+\dfrac{3}{3} \right) \\\\= 3 \left( 3c+4d+1 \right) .\end{array}