Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set - Page 59: 123

$-\dfrac{14}{15}$

Using the $LCD= 15 $, the given expression, $ \dfrac{-4}{15}+\dfrac{2}{-3} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{1(-4)+(-5)(2)}{15} \\\\= \dfrac{-4-10}{15} \\\\= \dfrac{-14}{15} \\\\= -\dfrac{14}{15} .\end{array}