Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set: 123

Answer

$-\dfrac{14}{15}$

Work Step by Step

Using the $LCD= 15 $, the given expression, $ \dfrac{-4}{15}+\dfrac{2}{-3} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{1(-4)+(-5)(2)}{15} \\\\= \dfrac{-4-10}{15} \\\\= \dfrac{-14}{15} \\\\= -\dfrac{14}{15} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.