Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set - Page 59: 123



Work Step by Step

Using the $LCD= 15 $, the given expression, $ \dfrac{-4}{15}+\dfrac{2}{-3} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{1(-4)+(-5)(2)}{15} \\\\= \dfrac{-4-10}{15} \\\\= \dfrac{-14}{15} \\\\= -\dfrac{14}{15} .\end{array}
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