Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.7 Multiplication and Division of Real Numbers - 1.7 Exercise Set - Page 59: 119



Work Step by Step

The given expression, $ \dfrac{7}{10}\div\left( \dfrac{-3}{5} \right) $, simplifies to \begin{array}{l}\require{cancel} \dfrac{7}{10}\cdot\left( \dfrac{5}{-3} \right) \\\\= \dfrac{7(5)}{10(-3)} \\\\= \dfrac{7(\cancel{5})}{\cancel{5}\cdot2(-3)} \\\\= \dfrac{7}{-6} \\\\= -\dfrac{7}{6} .\end{array}
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