Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.4 Positive and Negative Real Numbers - 1.4 Exercise Set - Page 36: 97

Answer

$a\lt0$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the concept of inequality to translate the given description, \begin{array}{l}\require{cancel} \text{a number $a$ is negative} ,\end{array} to symbols. $\bf{\text{Solution Details:}}$ Negative numbers are numbers less than $0.$ Hence, in symbols, the given description is equivalent to \begin{array}{l}\require{cancel} a\lt0 .\end{array}
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