Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.3 Fraction Notation - 1.3 Exercise Set - Page 28: 105


$\dfrac{138}{5} \text{ } cm$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Change the given length of the cube, $ 2\frac{3}{10} ,$ to an improper fraction. Then multiply the result by $12$ to get the total length of the edges of the cube. $\bf{\text{Solution Details:}}$ The mixed number, $a\frac{b}{c},$ is equivalent to $\dfrac{ac+b}{c}.$ Hence, the given length of the edge of the cube is equivalent to \begin{array}{l}\require{cancel} 2\frac{3}{10} \\\\= \dfrac{2(10)+3}{10} \\\\= \dfrac{23}{10} .\end{array} Since a cube has a total of $12$ equal edges, then the total length of the edges of the cube is \begin{array}{l}\require{cancel} \dfrac{23}{10}\cdot12 \\\\= \dfrac{23}{\cancel2(5)}\cdot\cancel2(6) \\\\= \dfrac{138}{5} \text{ } cm .\end{array}
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