Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.3 Fraction Notation - 1.3 Exercise Set: 27

Answer

$3^{3}$

Work Step by Step

A number is prime if it has only two factors: 1 and itself. We know that the factors of 27 are 1, 3, 9, and 27. 3 is a prime number, so we can divide 27 by 3 $27\div3=9$ The factors of 9 are 1, 3, and 9. Since 3 is a prime number, divide by 3. $9\div3=3$ 3 is also a prime number Therefore, the prime factorization of 27 is $3\times3\times3=3^{3}$.
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