Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.2 The Commutative, Associative, and Distributive Laws - 1.2 Exercise Set - Page 18: 102

Answer

$15x+40=5(3x+8)$ For $x=4$ $15x+40=15\cdot4+40=60+40=100$ For $x=4$ $5(3x+8)=5(3\cdot4+8)=5(12+8)=5(20)=100$ Since the values of $15x+40$ and $5(3x+8)$ are equal. Both the expressions are equivalent. Hence, the results guarantee that the factorization is correct.

Work Step by Step

Firstly make factors of $15$ as follows: $15=5\cdot3$ Now make factors of $40$ as follows: $40=5\cdot8$ Now write $15$ and $40$ in factor form in the expression $15x+40$. We get, $(5\cdot3)x+5\cdot8$ Now use Associative law. We get, $5(3x)+5\cdot8$ Now use the reverse of the Distributive law. We get, $5(3x+8)$ Here $5$ and $(3x+8)$ are the factors. Now substitute $x=4$ in $15x+40$. We get, $15\cdot4+40=60+40=100$ Now substitute $x=4$ in $5(3x+8)$. We get, $5(3\cdot4+8)=5(12+8)=5(20)=100$ Since the values of $15x+40$ and $5(3x+8)$ are equal. Both the expressions are equivalent. Hence, the results guarantee that the factorization is correct.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.