Answer
$f(4)=0$
Work Step by Step
Using $
4
$ in operating the coefficients of the given function, $f(x)=
x^4-6x^3+11x^2-17x+20
,$ results in the picture shown below.
The last row of numbers, $\{
1,-2,3,-5,0
\},$ represents the coefficients of the quotient and the remainder. Furthermore, the remainder of $\dfrac{f(x)}{x-c}$ is equal to $f(c)$. Hence, $
f(4)=0
$.