Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Appendix A - Mean, Median, and Mode - A Exercise Set - Page 985: 2

Answer

$\underline{\text{Mean}}:6$ $\underline{\text{Median}}: 7$ $\underline{\text{Mode}}: \text{None}$

Work Step by Step

$\underline{\text{Mean}}:$ $\text{Mean}$ = $\dfrac{\text{Sum of all observations}}{\text{Total no. of observations}}$ = $\dfrac{1+2+5+7+8+9+10}{7}=\dfrac{42}{7}=\boxed{6}$ $\underline{\text{Median}}:$ $\text{We can find the median by first arranging the given observation in the increasing order and find the mid-point of these observations. In this case, we get it as}$ $1, 2, 5, 7, 8, 9, 10$ $\text{There are 7 observations. So, the mid-point of these observations is given as}$ $\text{Mid-point} =\dfrac{n+1}{2}=\dfrac{7+1}{2}=\dfrac{8}{2}=4$. $\text{We have found out that the $3^{\text{rd}}$ observation of the arranged number is the median. The $3^{\text{rd}}$ observation in this arranged numbers is 18. That means, the median of this problem is $\boxed{7}$}$. $\underline{\text{Mode}}:$ $\text{Mode is the number that occurs the most. In this case, there is no number that occurs more than once. So, the mode of this question is $\boxed{\text{none}}$}$
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