Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - Chapters 1-9 Cumulative Review Problem Set - Page 433: 69



Work Step by Step

We will remove the parenthesis by multiplying each term within the parenthesis with the term outside the parenthesis. Then, we will put the variables and constants on opposite sides of the equality sign to simplify: Step 1: $-2(n-1)+4(2n-3)=4(n+6)$ Step 2: $-2n+2+8n-12=4n+24$ Step 3: $-2n+8n-4n=24+12-2$ Step 4: $2n=34$ Step 5: $n=17$
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