Answer
False
Work Step by Step
Step 1: $\sqrt x=x$
Step 2: Squaring both sides of the equation and simplifying, we obtain:
$(\sqrt x)^{2}=x^{2}$
$x=x^{2}$
Step 3: Rearranging the equation, we find: $x^{2}-x=0$
Step 4: Taking $x$ common and solving the equation;
$x^{2}-x=0$
$x(x-1)=0$
$x=0$ or $(x-1)=0$
$x=0$ or $x=1$
Therefore, the correct solution set of the equation is {$0,1$} which means that the question statement is false.
