## Elementary Algebra

Step 1: $\sqrt x=x$ Step 2: Squaring both sides of the equation and simplifying, we obtain: $(\sqrt x)^{2}=x^{2}$ $x=x^{2}$ Step 3: Rearranging the equation, we find: $x^{2}-x=0$ Step 4: Taking $x$ common and solving the equation; $x^{2}-x=0$ $x(x-1)=0$ $x=0$ or $(x-1)=0$ $x=0$ or $x=1$ Therefore, the correct solution set of the equation is {$0,1$} which means that the question statement is false.