Elementary Algebra

Simplifying the expression by using the rule $\sqrt [3] \frac{a}{b}=\frac{\sqrt[3] a}{\sqrt[3] b}$, we obtain: $\sqrt [3] \frac{27}{8}=\frac{\sqrt[3] {27}}{\sqrt[3] 8} =\frac{\sqrt[3] {3^{3}}}{\sqrt[3] 2^{3}}=\frac{3}{2}$ Therefore, the statement is true.