## Elementary Algebra

To find the simplest radical form, we will have to rationalize the denominator of the expression: $\sqrt \frac{9}{5}$ $=\frac{\sqrt 9}{\sqrt 5}$ $=\frac{\sqrt {3^{2}}}{\sqrt 5}$ $=\frac{3}{\sqrt 5}$ $=\frac{3}{\sqrt 5}\times\frac{\sqrt 5}{\sqrt 5}$ $=\frac{3\sqrt 5}{(\sqrt 5)^{2}}$ $=\frac{3\sqrt 5}{5}$ Therefore, it can be seen that the statement is false.