Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 9 - Roots and Radicals - 9.2 - Simplifying Radicals - Problem Set 9.2 - Page 407: 72


The answer is below.

Work Step by Step

$\sqrt{x^2} = x $ when x is positive. Thus, $\sqrt{x^2} = x$ for 5, 4, and 9. $\sqrt{x^2} $ never equals negative x, for a square root is never equal to a negative number. Thus, $\sqrt{x^2} $ equals the absolute value of x for negative values of x, including -3, -8, and -11.
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