Elementary Algebra

$3x-y=-16$
Using $y-y_1=m(x-x_1)$ or the Point-Slope Form, the equation of the line with the given point $( -6,-2 )$ and slope $m= 3$ is \begin{array}{l}\require{cancel} y-(-2)=3(x-(-6)) \\\\ y+2=3(x+6) \\\\ y+2=3x+18 \\\\ -3x+y=18-2 \\\\ -3x+y=16 \\\\ 3x-y=-16 .\end{array}