## Elementary Algebra

Published by Cengage Learning

# Chapter 7 - Algebraic Fractions - Chapter 7 Test: 11

#### Answer

$\frac{2n-6}{n(n-1)}$

#### Work Step by Step

First, we find the least common multiple of the denominators of the fractions. This, upon inspection, is found to be $n(n-1)$. Then, we use the least common multiple to create a common denominator, allowing us to subtract the fractions: $\frac{6}{n}-\frac{4}{n-1}$ =$\frac{6(n-1)-4(n)}{n(n-1)}$ =$\frac{6n-6-4n}{n(n-1)}$ =$\frac{6n-4n-6}{n(n-1)}$ =$\frac{2n-6}{n(n-1)}$

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