## Elementary Algebra

Let t be the time it takes Pipe A. Thus: $1/ 3 = \frac{1}{t} + \frac{1}{t+8}$ We create common denominators to obtain: $.33 = \frac{t+t+8}{t(t+8)} \\ .33t^2 + 2.67t = 2t +8 \\ .33t^2 +.67t -8 = 0 \\ t^2 +2t -24 = 0 \\(t+6)(t-4) =0$ Since t can't be negative, we see that it takes Pipe A 4 hours. This means it takes Pipe B 4+8=12 hours.