## Elementary Algebra

We first create common denominators: $\frac{x(x+2)}{3(x-2)(x+2)} + \frac{12}{3(x-2)(x+2)} = \frac{(x+2)(x-2)}{3(x-2)(x+2)}$ The denominators are the same, so we can cancel them out to find: $x^2+ 2x +12 = x^2 -4 \\ 2x = -16 \\x=-8$ The given statement is true.