Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - Chapter 6 Review Problem Set - Page 273: 13



Work Step by Step

Using the rules of factoring trinomials to factor the polynomial, we obtain: $3n^{2}+3n-90$ =$3(n^{2}+n-30)$ =$3(n^{2}-5n+6n-30)$ =$3[n(n-5)+6(n-5)]$ =$3(n-5)(n+6)$
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