## Elementary Algebra

$(5y+2)(y-7)$
In accordance with the rules of factoring trinomials, we need to find two integers whose product is $-70$ and whose sum is $-33$. A little searching determines that these numbers are $2$ and $-35$. Therefore, we can express the middle term $-33y$ as $(+2y-35y)$ and proceed to factoring by grouping: $5y^{2}-33y-14$ =$5y^{2}+2y-35y-14$ =$y(5y+2)-7(5y+2)$ =$(5y+2)(y-7)$