Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.2 - Factoring the Difference of Two Squares - Concept Quiz 6.2 - Page 247: 5



Work Step by Step

While $y^4-81$ can indeed be factored to $(y^2+9)(y^2-9)$, this is not the completely factored form of the expression. The factor $y^2-9$ is the difference of two perfect squares and can be further factored down to $(x-3)(x+3)$. This gives us a completely factored expression of $(x^2+9)(x+3)(x-3)$.
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