Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 6 - Factoring, Solving Equations, and Problem Solving - 6.1 - Factoring by Using the Distributive Property - Concept Quiz 6.1: 5

Answer

False

Work Step by Step

The person who factored the expression did not take out the $\text{GCF}$, so the expression is not factored completely. The $\text{GCF}$ is $6a$, not $3a$, which makes the completely factored version $6a(a^2+2)$, not $3a(2a^2+4)$.
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