Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - Chapter 5 Review Problem Set: 23

Answer

$x^2-3x-10$

Work Step by Step

RECALL For any real numbers a, b, and c: $a(b+c)=ab + ac$ Use the distributive property (which is shown above) to obtain: $=x(x+2) - 5(x+2) \\=x(x) + x(2) - 5(x) - 5(2) \\=x^2+2x-5x-10 \\=x^2+(2-5)x-10 \\=x^2+(-3)x-10 \\=x^2-3x-10$
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