Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 5 - Exponents and Polynomials - 5.5 - Dividing by Binomials - Concept Quiz 5.5 - Page 217: 7

Answer

True

Work Step by Step

$x-1$ is a factor of $x^3 -1$, so it does have a remainder of 0.
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