## Elementary Algebra

Published by Cengage Learning

# Chapter 5 - Exponents and Polynomials - 5.3 - Multiplying Polynomials - Problem Set 5.3 - Page 207: 7

#### Answer

$xy+xz+x+2y+2z+2$

#### Work Step by Step

Using the Distributive Property, the given expression, $(x+2)(y+z+1) ,$ is equivalent to \begin{array}{l}\require{cancel} x(y)+x(z)+x(1)+2(y)+2(z)+2(1) \\\\= xy+xz+x+2y+2z+2 .\end{array}

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