## Elementary Algebra

$\frac{2}{5}$$x^{3}$$y^{5}$
($\frac{2}{3}$xy)($\frac{3}{5}$$x^{2}$$y^{4}$) = Use $b^{n}$ $b^{m}$ = $b^{m+n}$ to simplify. $\frac{2}{3}$ $\times$ $\frac{3}{5}$ $\times$ $x^{1+2}$ $\times$ $y^{1+4}$ = $\frac{2}{5}$$x^{3}$$y^{5}$