## Elementary Algebra

Published by Cengage Learning

# Chapter 3 - Equations and Problem Solving - Chapter 3 Review Problem Set - Page 138: 47

#### Answer

The width of the rectangle is 15 cm. The length of the rectangle is 40cm.

#### Work Step by Step

We can let w represent the width. The length of the rectangle was 10 centimeters longer than twice the width. Twice the width means 2w. 10 centimeters longer than twice the width means 2w + 10. So, the length is 2w + 10. The formula for the perimeter of the rectangle is width + width + length + length The perimeter of the rectangle is 110 cm, so we set up the following equation: w + w + 2w + 10 + 2w + 10 = 110 6w + 20 = 110 6w = 90 Divide both sides by 6. w = 15 The width of the rectangle is 15 cm. The length is 2 $\times$ 15 + 10 = 40 cm.

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