Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 3 - Equations and Problem Solving - Chapter 3 Review Problem Set: 47

Answer

The width of the rectangle is 15 cm. The length of the rectangle is 40cm.

Work Step by Step

We can let w represent the width. The length of the rectangle was 10 centimeters longer than twice the width. Twice the width means 2w. 10 centimeters longer than twice the width means 2w + 10. So, the length is 2w + 10. The formula for the perimeter of the rectangle is width + width + length + length The perimeter of the rectangle is 110 cm, so we set up the following equation: w + w + 2w + 10 + 2w + 10 = 110 6w + 20 = 110 6w = 90 Divide both sides by 6. w = 15 The width of the rectangle is 15 cm. The length is 2 $\times$ 15 + 10 = 40 cm.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.