## Elementary Algebra

$\dfrac{10}{25}$ is not yet reduced to lowest terms since the numerator and the denominator still have a common factor of $5$. Note that: $\require{cancel} \\\dfrac{10}{25} \\=\dfrac{5(2)}{5(5)} \\=\dfrac{\cancel{5}(2)}{\cancel{5}(5)} \\= \dfrac{2}{5}$ Thus, the given statement is false.