The answer is below
Work Step by Step
The height of a ball that I throw is equal to $h(t) = -16t^2 + 32t$. The height at certain values of time are: $$h(0) = 0 \\ h(1) = 16 \\ h(2) = 0$$
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.