Answer
The answer is below
Work Step by Step
The height of a ball that I throw is equal to $h(t) = -16t^2 + 32t$. The height at certain values of time are:
$$h(0) = 0 \\ h(1) = 16 \\ h(2) = 0$$
Elementary Algebra
by Kaufmann, Jerome; Schwitters, Karen;
Published by
Cengage Learning
ISBN 10:
1285194055
ISBN 13:
978-1-28519-405-9
Chapter 11 - Additional Topics - 11.8 - Applications of Functions - Problem Set 11.8: 24
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