Elementary Algebra

Published by Cengage Learning
ISBN 10: 1285194055
ISBN 13: 978-1-28519-405-9

Chapter 11 - Additional Topics - 11.5 - Quadratic Equations: Complex Solutions - Problem Set 11.5 - Page 497: 22



Work Step by Step

Using the rules of factoring trinomials to factor, we obtain: $3x^{2}-5x-2=0$ $3x^{2}+1x-6x-2=0$ $x(3x+1)-2(3x+1)=0$ $(3x+1)(x-2)=0$ $(3x+1)=0$ or $(x-2)=0$ $x=-\frac{1}{3}$ or $x=2$ Therefore, the solution set is {$-\frac{1}{3},2$}.
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