# Chapter 11 - Additional Topics - 11.5 - Quadratic Equations: Complex Solutions - Concept Quiz 11.5: 6

True

#### Work Step by Step

Using the rules for factoring trinomials, we obtain: $12x^{2}-7x-12=0$ $12x^{2}+9x-16x-12=0$ $3x(4x+3)-4(4x+3)=0$ $(4x+3)(3x-4)=0$ $(4x+3)=0$ or $(3x-4)=0$ $x=-\frac{3}{4}$ or $x=\frac{4}{3}$ Therefore, the solution can be solved by factoring.

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