Answer
True
Work Step by Step
To multiply complex numbers, we multiply each term of the first number by each term of the second number and then simplify.
$(-2-i)(-3+2i)$
$=(-2)(-3)+(-3)(-i)+(-2)(2i)+(-i)(2i)$
$=6+3i-4i-2i^2$
$=6-i-2i^2$
Since $i^2=-1$, we obtain: $6-i-2(-1)=6-i+2=8-i$
