## Elementary Algebra

To multiply complex numbers, we multiply each term of the first number by each term of the second number and then simplify. $(-2-i)(-3+2i)$ $=(-2)(-3)+(-3)(-i)+(-2)(2i)+(-i)(2i)$ $=6+3i-4i-2i^2$ $=6-i-2i^2$ Since $i^2=-1$, we obtain: $6-i-2(-1)=6-i+2=8-i$