## Elementary Algebra

We simplify both the expressions to see if they are equivalent or not: $\sqrt[n] {x^{m}}=(x^{m})^{\frac{1}{n}}=x^{\frac{m}{n}}$ $(\sqrt[n] x)^{m}=(x^{\frac{1}{n}})^{m}=x^{\frac{1}{n}\times m}=x^{\frac{m}{n}}$ Therefore, the two expressions are equivalent and the question statement is true.