## Elementary Algebra

Let c be the cost of the chef, m be the cost of the salad maker, and s be the cost of the server. Thus, we obtain: $c + m + s = 70 \\ m = s +5 \\ c = s + m$ We plug equation three into equation one to find: $c + c = 70 \\ c = 35$ We plug equation two into equation three to find: $c = s + s + 5 \\ 35 = 2s +5 \\ 2s = 30 \\ s= 15$ Thus, we obtain: $m = s+5 = 15 + 5 = 20$