Work Step by Step
For any real number $a$, $|a| \ge 0$. This means that the absolute value of any number or quantity is always greater than or equal to 0. Thus, in the given inequality, the value of $|x-2|$ is always greater than or equal to 0. Since $-6 \lt 0$, then, for any real number $x$, $|x-2| \ge -6$. The given statement is true.