## Elementary Algebra

Published by Cengage Learning

# Chapter 10 - Quadratic Equations - 10.5 - Solving Problems Using Quadratic Equations - Problem Set 10.5: 32

#### Answer

The side is 9 feet, and the altitude is 4 feet.

#### Work Step by Step

We are told: $l = 2h +1$ Using the formula for the area of a triangle, we find: $A = .5lh \\ 18 = .5(2h+1)(h) \\ 0 = h^2 + .5h - 18 \\ 0 = 2h^2 + h -36 \\ (h-4)(2h+9)$ Since h can't be negative, we see that h=4. This means that: $l = 2(4) + 1 = 9.$

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