# Chapter 10 - Quadratic Equations - 10.1 - Quadratic Equations - Problem Set 10.1: 83

10.8 cm

#### Work Step by Step

First, we must find the length of the diagonal along the bottom of the cube: $a^2 + b^2 = c^2 \\ c = \sqrt{a^2 + b^2} \\ c = \sqrt{6^2 + 8^2} =10$ We now find the length of the diagonal from the lower to the upper corner: $c = \sqrt{a^2 + b^2} \\ c = \sqrt{10^2 + 4^2} = 10.8$

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