# Chapter 1 - Some Basic Concepts of Arithmetic and Algebra - Chapter 1 Test - Page 39: 19

$3\times2\times3\times2\times5\times2$

#### Work Step by Step

First, we divide $360$ by $10$ to get $36$. Therefore, $360=36\times10$ We will continue to do this until we are left with only prime numbers. Next, we break down the $36$ into two sixes, giving us $6\times6\times10$ We break down each six into its two prime factors, $2$ and $3$: $2\times3\times2\times3\times10$ Finally, we break $10$ down into its two prime factors, $5$ and $2$, giving us $3\times2\times3\times2\times5\times2$

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