Elementary Algebra

We consider the unknown length of the box as $x$ inches. Therefore, one-half the length is $\frac{x}{2}$ inches. Since the width ($8$ inches) is $1$ inch more than one-half the length, we write the following equation and solve: $8= \frac{x}{2}+1$ $8-\frac{x}{2}=1$ $\frac{8(2)-x}{2}=1$ $\frac{16-x}{2}=1$ $16-x=2$ $x=16-2$ $x=14$ Therefore, the length is 14 inches.