Answer
See below
Work Step by Step
We are given:
$x'=x(2x+y)\\
y'=y(x-2y+4)$
To find equilibrium points, we take:
$0=x(2x+y)\\
0=y(x-2y+4)$
Solving:
$(x,y)$$=(0,2)\\
=(0,0)\\
=(-\frac{4}{5},\frac{8}{5})$
Differential Equations and Linear Algebra (4th Edition)
by Goode, Stephen W.; Annin, Scott A.
Published by
Pearson
ISBN 10:
0-32196-467-5
ISBN 13:
978-0-32196-467-0
Chapter 9 - Systems of Differential Equations - 9.9 The Phase Plane for Linear Autonomous Systems - Problems - Page 653: 3
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